Exercise-12.1
Question 1:
Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.
(i) Subtraction of z from y.
(ii) One-half of the sum of numbers x and y.
(iii) The number z multiplied by itself.
(iv) One-fourth of the product of numbers p and q.
(v) Numbers x and y both squared and added.
(vi) Number 5 added to three times the product of numbers m and n.
(vii) Product of number y and z subtracted from 10.
(viii) Sum of numbers a and b subtracted from their product.
Answer:
(i) y – x
(ii)1/2( x+y )
(iii)Z2
(iv) 1/4( pq )
(v)x2+y2
(vi)5 + 3 (mn)
(vii) 10 -(yz)
(viii) ab-(a+b)
Question 2:
(i) Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams.
(a) x – 3
(b) 1 + x + x2
(c) y – y3
(d) 5xy2 + 7x2y
(e) -ab + 2b2 – 3a2
(ii) Identify terms and factors in the expression given below:
(a) -4x + 5
(b) -4x + 5y
(c) 5y + 3y2
(d) xy + 2x2y2
(e) pq + q






Exercise-12.2
Question 1:
Simplify combining like terms:
(i) 21b – 32 + 7b – 20b
(ii)-z2 + 13z2 – 5z + 7z3 -15z
(iii) p -(p – q) – q – (q – p)
(iv) 3a – 2b – ab -(a – b + ab) + 3ab + b -a
(v) 5x2y -5x2 + 3yx2 -3y2 + x2 – y2 + 8xy2 -3y2
(vi) (3y2 + 5y -4) – (8y – y2 -4)
Answer:
The parts of the given questions are solved as follows:
(i) It is given in the question that,
We have to simplify the expression by combining like terms:
21b – 32 + 7b – 20b
= 21b – 20d +7b – 32
= (21 – 20 + 7)b – 32
= 8b – 32
(ii) It is given in the question that,
We have to simplify the expression by combining like terms:
-z2 + 13z2 – 5z + 7z3 -15z
= – z2 + 13z2 + 7z3 – 5z – 15z
= z2(- 1 + 13) + 7z3 – z(5+15)
= 12z2 + 7z3 – 20z
(iii) It is given in the question that,
We have to simplify the expression by combining like terms:
p -(p – q) – q – (q – p)
= p – p + q – q – q +p
= p – p + p + q – q – q
= p – q
(iv) It is given in the question that,
We have to simplify the expression by combining like terms:
3a – 2b – ab -(a – b + ab) + 3ab + b -a
= 3a – 2b – ab – a + b – ab + 3ab + b – a
= 3a – a – a – 2b + b + b – ab – ab + 3ab
= (3 – 1 – 1)a–b(2 – 1 – 1) -ab(1 + 1 – 3)
= a + ab
(v) It is given in the question that,
We have to simplify the expression by combining like terms:
5x2y -5x2 + 3yx2 -3y2 + x2 – y2 + 8xy2 -3y2
= 5x2y + 3x2y – 5×2 + x2 – 3y2 –y2 – 3y2 + 8xy2
= (5 + 3)x2y + (– 5 + 1)x2 + (– 3 – 1 – 1)y2 + 8xy2
= 8x2y – 4×2 – 5y2 + 8xy2
(vi) It is given in the question that,
We have to simplify the expression by combining like terms:
(3y2 + 5y -4) – (8y – y2 -4)
= 3y2+ 5y – 4 – 8y + y2 + 4
= 3y2 + y2 + 5y – 8y – 4 + 4
= 4y2 – 3y




Exercise-12.3




Exercise-12.4


