# class 7 Maths Chapter-8 Comparing Quantities

Question 1:
Find ratio of:
(a) Rs. 5 to 50 paise
(b) 15 kg to 210 g
(c) 9 m to 27 cm
(d) 30 days to 36 hours

(a) Rs. 5 to 50 paise
We have,
Rs 5 to 50 Paise
We know that,
1 Rupee = 100 paise
Therefore,
5 Rupees = 500 Paise
Hence,
Ratio = Rs 5/50 Paise
= 500/50
= 10/1
Therefore,
Required ratio = 10: 1

(b) 15 kg to 210 g
We have,
15 kg to 210 g
We know that,
1 kg = 1000 g
Therefore,
15 kg = 15000 g
Hence,
Ratio = 15 kg/210 g
= 15000/210
= 500/7
Therefore,
Required ratio = 500: 7

(c) 9 m to 27 cm
We have,
9 m to 27 cm
We know that,
1 m = 100 cm
Therefore,
9 m = 900 cm
Hence,
Required ratio = 9 m/27 cm
= 900/27
= 100/3
Therefore,
Required ratio = 100: 3

(d) 30 days to 36 hours
We have,
30 days to 36 hours
We know that,
1 day = 24 hours
Therefore,
30 days = 30 × 24
= 720 hours
Hence,
Required ratio = 30 days/36 hours
= 720/36
= 20/1
Therefore,
Required ratio = 20: 1

Question 2:
In a computer lab, there are 3 computers for every 6 students.  How many computers will be needed for 24 students?

### Exercise-8.3

Question 1:
Tell what is the profit or loss in the following transactions.  Also find profit per cent or loss per cent in each case
(a) Gardening shears bought for Rs. 250 and sold for Rs. 325.
(b) A refrigerator bought for Rs. 12,000 and sold at Rs. 13,500.
(c) A cupboard bought for Rs. 2,500 and sold at Rs. 3,000.
(d) A skirt bought for Rs. 250 and sold at Rs. 150.

(a) It is given in the question that,
Cost price of the product = Rs 250
Also,
Selling price of the product = Rs 325
Therefore,
Profit = Selling Price – Cost Price
= 325 – 250
= Rs 75

Selling price of the refrigerator = Rs 13,500

Therefore,

Profit = Selling Price – Cost Price

= 13,500 – 12,000

= Rs 1500

We know that,

(d) It is given in the question that,

Cost price of the skirt = Rs 250

Also,

Selling price of the skirt = Rs 150

Therefore,

Loss = Cost Price – Selling Price

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