CLASS 8 MATHS CHAPTER -10 VISUALISING SOLID SHAPES

Exercise 10.1

Question 1.

For each of the given solid, the two views are given. Match for each solid the corresponding top and front views. The first one is done for you.
Visualising Solid Shapes\11.jpg

Solution :

(a) Visualising Solid Shapes/image002.png (iii); Visualising Solid Shapes/image002.png(iv)
(b); Visualising Solid Shapes/image002.png(i); Visualising Solid Shapes/image002.png; (v)
(c); Visualising Solid Shapes/image002.png(iv) Visualising Solid Shapes/image002.png (ii)
(d)Visualising Solid Shapes/image002.png (v); Visualising Solid Shapes/image002.png(iii)
(e) Visualising Solid Shapes/image002.png (ii); Visualising Solid Shapes/image002.png(i)
;

Question 2.

For each of the given solid, the three views are given. Identify for each solid the corresponding top, front and side views.
;Visualising Solid Shapes/image003.jpg


Visualising Solid Shapes/image005.png

SolutionVisualising Solid Shapes/image004.png:

(a);Visualising Solid Shapes/image002.png(i); Front
(ii) Visualising Solid Shapes/image002.png Side
(iii) Visualising Solid Shapes/image002.png Top view
(b) Visualising Solid Shapes/image002.png (i); Side
(ii) Visualising Solid Shapes/image002.png Front
(iii)Visualising Solid Shapes/image002.png; Top view
(c) Visualising Solid Shapes/image002.png (i); Front
(ii); Visualising Solid Shapes/image002.pngSide
(iii) Visualising Solid Shapes/image002.png Top view
(d) Visualising Solid Shapes/image002.png (i); Front
(ii); Visualising Solid Shapes/image002.pngSide
(iii); Visualising Solid Shapes/image002.pngTop view

Question 3.

For each given solid, identify the top view, front view and side view.
Visualising Solid Shapes/image006.jpg
Visualising Solid Shapes/image007.jpg

Solution :

(a); Visualising Solid Shapes/image002.png(i) Visualising Solid Shapes/image002.png Top view Visualising Solid Shapes/image002.png(ii); Visualising Solid Shapes/image002.pngFront viewVisualising Solid Shapes/image002.png (iii); Visualising Solid Shapes/image002.pngSide view
(b) Visualising Solid Shapes/image002.png (i) Visualising Solid Shapes/image002.png Side viewVisualising Solid Shapes/image002.png (ii) Visualising Solid Shapes/image002.png Front viewVisualising Solid Shapes/image002.png (iii); Visualising Solid Shapes/image002.pngTop view
(c); Visualising Solid Shapes/image002.png(i); Visualising Solid Shapes/image002.pngTop viewVisualising Solid Shapes/image002.png (ii)Visualising Solid Shapes/image002.png; Side viewVisualising Solid Shapes/image002.png (iii) Visualising Solid Shapes/image002.png Front view
(d); Visualising Solid Shapes/image002.png(i) Visualising Solid Shapes/image002.png Side view Visualising Solid Shapes/image002.png(ii) Visualising Solid Shapes/image002.png Front viewVisualising Solid Shapes/image002.png (iii) Visualising Solid Shapes/image002.png Top view
(e) Visualising Solid Shapes/image002.png (i); Visualising Solid Shapes/image002.pngFront view Visualising Solid Shapes/image002.png(ii)Visualising Solid Shapes/image002.png; Top viewVisualising Solid Shapes/image002.png (iii) Visualising Solid Shapes/image002.png Side view

Question 4.

Draw the front view, side view and top view of the given objects:
Visualising Solid Shapes/image008.png

Solution :
Visualising Solid Shapes/image009.jpg
Visualising Solid Shapes/image010.jpg
Visualising Solid Shapes/image011.jpg

NCERT Solutions for Class 8 Maths Exercise 10.2


Question 1.

Can a polygon have for its faces:
(i) 3 triangles ;
(ii) 4 triangles
(iii) a square and four triangles

Solution :

(i) No, a polyhedron cannot have 3 triangles for its faces.
(ii) Yes, a polyhedron can have four triangles which is known as pyramid on triangular base.
(iii) Yes, a polyhedron has its faces a square and four triangles which makes a pyramid on square base.

Question 2.

Is it possible to have a polyhedron with any given number of faces? (Hint: Think of a pyramid)

Ans.

It is possible, only if the number of faces are greater than or equal to 4.

Question 3.

Which are prisms among the following:
Visualising Solid Shapes/image001.jpg

Solution :

Figure (ii) unsharpened pencil and figure (iv) a box are prisms.

Question 4.

(i) How are prisms and cylinders alike?
(ii) How are pyramids and cones alike?

Solution :

(i) A prism becomes a cylinder as the number of sides of its base becomes larger and larger.
(ii) A pyramid becomes a cone as the number of sides of its base becomes larger and larger.

Question 5.

Is a square prism same as a cube? Explain.

Solution :

No, it can be a cuboid also.

Question 6.

Verify Euler’s formula for these solids.
Visualising Solid Shapes/image002.png

Solution :

(i) Here, figure (i) contains 7 faces, 10 vertices and 15 edges.
Using Eucler’s formula, we see
Visualising Solid Shapes/image003.pngF + V – E = 2
Putting F = 7, V = 10 and E = 15,
Visualising Solid Shapes/image003.pngF + V – E = 2
Visualising Solid Shapes/image003.png7 + 10 – 5 = 2
Visualising Solid Shapes/image003.png 17 – 15 = 2
Visualising Solid Shapes/image003.png2 = 2
Visualising Solid Shapes/image003.pngL.H.S. = R.H.S.
(ii); Here, figure (ii) contains 9 faces, 9 vertices and 16 edges.
Using Eucler’s formula, we see
F + V – E = 2
F + V – E = 2
Visualising Solid Shapes/image003.png 9 + 9 – 16 = 2
Visualising Solid Shapes/image003.png 18 – 16 = 2
Visualising Solid Shapes/image003.png 2 = 2
Visualising Solid Shapes/image003.png L.H.S. = R.H.S.
Hence verified Eucler’s formula.

Question 7.

Using Euler’s formula, find the unknown:

Faces?520
Vertices6?12
Edges129?

Solution :

In first column, F = ?, V = 6 and
E = 12
Using Eucler’s formula, we see
F + V – E = 2
F + V – E = 2
;F + 6 – 12 = 2
;F – 6 = 2
;F = 2 + 6 = 8
Hence there are 8 faces.
In second column, F = 5, V = ? and E = 9
Using Eucler’s formula, we see
F + V – E = 2
F + V – E = 2
;5 + V – 9 = 2
;V – 4 = 2
;V = 2 + 4 = 6
Hence there are 6 vertices.
In third column, F = 20, V = 12 and E = ?
Using Eucler’s formula, we see
F + V – E = 2
F + V – E = 2
;20 + 12 – E = 2
;32 – E = 2
;E = 32 – 2 = 30
 Hence there are 30 edges.

Question 8.

Can a polyhedron have 10 faces, 20 edges and 15 vertices?

Solution :

If F = 10, V = 15 and E = 20.
Then, we know Using Eucler’s formula,
F + V – E = 2
L.H.S. = F + V – E
= 10 + 15 – 20
= 25 – 20
= 5
R.H.S.; = 2
 Hence  L.H.S. R.H.S.
Therefore, it does not follow Eucler’s formula.
So polyhedron cannot have 10 faces, 20 edges and 15 vertices.

NCERT Solutions for Class 8 Maths Exercise 10.3

Visualising Solid Shapes\12.jpg
Visualising Solid Shapes\13.jpg
Visualising Solid Shapes\14.jpg

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